Creative thoughts-10
Power of a number as the difference of two squares
Any power of a number can be expressed as the difference between two squares ,
where the sum and difference of its roots give higher and lower powers of that number,
so that the product of them is exactly equal to the initial power of the number. This can be
applied effectively to any power of any number.
Cubes
1x1x1 = 1 = 1x1 – 0x0 ; 1 + 0 = 1 = 1x1 ; 1-0 = 1
2x2x2 =8 = 3x3 – 1x1 ; 3 + 1 = 4 = 2x2 ; 3-1 = 2
3x3x3 = 27 = 6x6 – 3x3 ; 6 + 3 = 9 =3x3 ; 6 – 3 = 3
4x4x4 = 64 = 10x10 – 6x6 ; 10 + 6 = 16 = 4x4 ; 10-6 = 4
5x5x5 = 125 = 15x15 – 10x10 ; 15 +10 = 25 = 5x5 ; 15-10= 5
It is found that all the squares involved in these relations are related to triangular numbers
( as they can be represented by triangles). The first few triangular numbers are 1,3,6,10,
15,21,28,36,45,……… The n th triangular number is the sum of n natural numbers from
1 and it is equal to n(n+1)/2. The cube of a number N is found to be the difference
between two successive triangular numbers ,whose sum gives square of the cube
root and the difference ,the cube root itself.
NxNxN = [N(N+1)/2] x [N(N+1)/2] - [N(N-1)/2]x[N(N-1)/2]
If T(n) denotes the n th triangular number ,then
T(n) + T (n-1) = n x n
T(n) – T(n-1) = n
4 th power of a number
The fourth power of a number N is equal to the difference of two squares, the sum
of its roots is equal to cube of that number and the difference of its roots is equal to
the number Itself.
2x2x2x2 = 16 = 5x5 – 3x3 ; 5+3 = 8 = 2x2x2 ; 5-3 = 2
3x3x3x3 = 81 = 15x15 – 12x12 ; 15 + 12 = 27 = 3x3x3 ; 15-12 = 3
4x4x4x4 = 256 = 34x34 – 30x30 ; 34 +30 = 64 = 4x4x4 ; 34-30 = 4
5x5x5x5 = 625 = 65x65-60x60 ; 65+60 = 125 =5x5x5 ;; 65-60 = 5
If N is any number
NxNxNxN = (N/2)[(NxN+1)(NxN+1)] – (N/2)[(NxN-1)(NxN-1)]
The smaller square root number in thes relations is (N-1) times the sum of N numbers
from 1 in the natural series and the greater square root number is obtained by adding N
with it.
No comments:
Post a Comment